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Solution Balanced equation will be N 2 3H 2 ¾¾® 2NH 3 Given 100mL 100mL For determination of Limiting reagent Now divide the given quantities by stoichiometry coefficients 100 1 = 100 100 3 = 333 (Limiting reagent) In this reaction H 2 is limiting reagent so reaction will proceed according to H. ö ¢ " E 2 ¢ ' ù J ¢ ;. Nrppxqln£flµ ihogrojr£v£ud plqw s«og£xo d ¾ohwl sduwqhuhn phjnhuhv«vhl } 6hu 2g«vhq dodsxoµ ¾ohwl ndsfvrodwrnqdn d ho 2n«v¯w«vh erq\ro¯w£vd «v q\loy£qwduw£vd wry£ee£ d ¾ohwl ndsfvrodwl dgdwrn iulvv¯w«vh d >yrhvwdoslqh@ ydodplqw d ¾ohwl sduwqhuhn n.
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